2x^2=253

Solution for 2x^2=253 equation:

2x^2=253

We move all terms to the left:

2x^2-(253)=0

a = 2; b = 0; c = -253;
Δ = b2-4ac
Δ = 02-4·2·(-253)
Δ = 2024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2024}=\sqrt{4*506}=\sqrt{4}*\sqrt{506}=2\sqrt{506}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{506}}{2*2}=\frac{0-2\sqrt{506}}{4}
=-\frac{2\sqrt{506}}{4}
=-\frac{\sqrt{506}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{506}}{2*2}=\frac{0+2\sqrt{506}}{4}
=\frac{2\sqrt{506}}{4}
=\frac{\sqrt{506}}{2}
$